Stephen Drew has reportedly signed a one-year deal with the Red Sox, according to FoxSports.com.
The shortstop became a free agent at the end of last season after winning the World Series with Boston and has agreed a 12 month deal to rejoin the same club.
The 31-year-old refused to re-sign for the Red Sox in the offseason to test the free-agent market but remained unsigned. If the agreement is confirmed by the club it would provide an ideal situation for both the team and the player.
The Red Sox have not yet confirmed the deal but are expected to add Drew to their roster by the end of the week.
FoxSports.com reported the deal would be for one season and the shortstop would become a free agent in the off season.
The Red Sox have struggled to defend their World Series title this year with a 20-23 record and lost out 6-2 against the Detroit Tigers recently. Drew would bolster the Red Sox ranks and could bring back the winning mentality which led the club to their eighth World Series in 2013.
Drew was described as one of the highest profile free agents on the open market in the winter by MLB.com but the shortstop failed to attract a club.
Last season Drew was one of the star players for the Red Sox while playing shortstop. The veteran had a .253 batting average with 13 home runs and .333 on-base percentage last season.
Rookie Xander Bogaerts has taken the shortstop role this season and performed effectively without being outstanding. Batting at an .269 average with a .369 on-base percentage Bogaerts has settled into life in MLB and has also played at third base, covering for Will Middlebrooks who broke his right index finger.
The injury has placed Middlebrooks on the 15-day disabled list, meaning Bogaerts will be required at third and Drew would fill in at shortstop.
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